document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=280049>Question 280049</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If the measure of the vertex angle of an isosceles triangle is 24degrees less than the sum of the measures of its base angles, then the measure of one of its base angles is:\r<BR>\n" );
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document.write( "(A) 156 degrees (B) 66 degrees  (C) 24 degrees (D) 78 degrees  (E) 51 degrees </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #203492 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=203492\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If the measure of the vertex angle of an isosceles triangle is 24degrees less than the sum of the measures of its base angles, then the measure of one of its base angles is:\r<BR>\n" );
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document.write( "(A) 156 degrees (B) 66 degrees  (C) 24 degrees (D) 78 degrees  (E) 51 degrees\r<BR>\n" );
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document.write( "let the vertex angle be x\r<BR>\n" );
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document.write( "the sum of the other two angles = 180-x\r<BR>\n" );
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document.write( "x+24 = 180-x\r<BR>\n" );
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document.write( "2x=180-24\r<BR>\n" );
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document.write( "2x=156\r<BR>\n" );
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document.write( "x= 78\r<BR>\n" );
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document.write( "180-78 will be the aum of the other two equal angles\r<BR>\n" );
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document.write( "180-78 /2  will be the angle =51\r<BR>\n" );
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document.write( " </SPAN>\n" );
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