document.write( "Question 280026: Not wanting to be embarrassed by revealing her age on her birthday, Grandma instead told the grandkids that if they multiplied her age in 5 years by 5, then multiplied her age in 6 years by 6, and added the two totals together, they would get a number that is 12 times her current age. When she saw the large wax forest fire atop her birthday cake , Grandma knew they had figured it out. How old is she? \n" ); document.write( "
Algebra.Com's Answer #203490 by mananth(16946)\"\" \"About 
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Not wanting to be embarrassed by revealing her age on her birthday, Grandma instead told the grandkids that if they multiplied her age in 5 years by 5, then multiplied her age in 6 years by 6, and added the two totals together, they would get a number that is 12 times her current age. When she saw the large wax forest fire atop her birthday cake , Grandma knew they had figured it out. How old is she? \r
\n" ); document.write( "\n" ); document.write( "let her age be x now\r
\n" ); document.write( "\n" ); document.write( "after 5 years\r
\n" ); document.write( "\n" ); document.write( "(x+5)*5\r
\n" ); document.write( "\n" ); document.write( "after 6 years\r
\n" ); document.write( "\n" ); document.write( "(x+6)*6\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "5(x+5) +6(x+6) = 12x\r
\n" ); document.write( "\n" ); document.write( "5x+25+6x+36=12x\r
\n" ); document.write( "\n" ); document.write( "11x+61=12x\r
\n" ); document.write( "\n" ); document.write( "12x-11x=61\r
\n" ); document.write( "\n" ); document.write( "x=61\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "
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