document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=280008>Question 280008</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 5(1+e^x/3)=8.2<BR>\n" );
document.write( "What does x equal? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #203485 by </B><A HREF=/tutors/aboutme.mpl?userid=nabla><B>nabla(475)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nabla><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=203485\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Manipulate to isolate e^x.\r<BR>\n" );
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document.write( "5(1+e^x/3)=8.2<BR>\n" );
document.write( "1+e^x/3=8.2/5=41/25<BR>\n" );
document.write( "e^x/3=41/25  - 25/25<BR>\n" );
document.write( "e^x=3*16/25=48/25\r<BR>\n" );
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document.write( "Now, we get rid of e by taking the natural logarithm of both sides of the equation.\r<BR>\n" );
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document.write( "ln(e^x)=ln(48/25)\r<BR>\n" );
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document.write( "By definition this is the same as:\r<BR>\n" );
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document.write( "x=ln(48/25)\r<BR>\n" );
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document.write( "And, using a calculator we find that x is approximately 0.652325 </SPAN>\n" );
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