document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=280016>Question 280016</A>: <I><SPAN STYLE=\"word-break: break-all;\"> THE DISTANCE BETWEEN THE PLANE x + 2y - 2z = 3 and 2x + 4y - 4z = 7 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #203481 by </B><A HREF=/tutors/aboutme.mpl?userid=nabla><B>nabla(475)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nabla><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=203481\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Note first that they are parallel planes (necessary).\r<BR>\n" );
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document.write( "When y=x=0 in x+2y-2z=3, there exists the point (0,0,-3/2)\r<BR>\n" );
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document.write( "D=|-4*(-3/2)-7|/sqrt(4+32)=1/6\r<BR>\n" );
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document.write( "It should be clear I skipped a few steps in showing the work, I assume you are able to do it. For more information see:\r<BR>\n" );
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document.write( "http://www.math.ucla.edu/~ronmiech/Calculus_Problems/32A/chap11/section5/718d65/718_65.html </SPAN>\n" );
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