document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=280013>Question 280013</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How do I solve the system using the substitution method and show work?<BR>\n" );
document.write( "2x+3y=2<BR>\n" );
document.write( "x+3y=10 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #203479 by </B><A HREF=/tutors/aboutme.mpl?userid=nabla><B>nabla(475)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nabla><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=203479\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Subtract the second equation from the first. You get\r<BR>\n" );
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document.write( "x=-8\r<BR>\n" );
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document.write( "Put that into the second (or first) equation to get y:\r<BR>\n" );
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document.write( "y=6<BR>\n" );
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document.write( "If you have difficulty understanding this material it is precisely due to pedantic requirements and a lack of intuitive explanations. </SPAN>\n" );
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