document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=33976>Question 33976</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A cashier at Apex Parts received a check for $2380 for 59 parts.  The parts cost $20 and $50 but the number wanted of each wasn't given.  How many of each can be bought with that amount? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #20344 by </B><A HREF=/tutors/aboutme.mpl?userid=Earlsdon><B>Earlsdon(6294)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Earlsdon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=20344\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x = the number that can be bought for $20.00 each, then (59-x) = the number that can be bought for $50.00 each. You can write:<BR>\n" );
document.write( "$20(x) + $50(59-x) = $2380 Simplify and solve for x.<BR>\n" );
document.write( "$20(x) + $2950 - $50x = $2380<BR>\n" );
document.write( "-$30(x) + $2950 = $2380 Subtract $2950 from both sides.<BR>\n" );
document.write( "-$30(x) = -$570 Divide both sides by -$30.<BR>\n" );
document.write( "x = 19<BR>\n" );
document.write( "59-x = 40\r<BR>\n" );
document.write( "\n" );
document.write( "19 can be bought at $20.00 each<BR>\n" );
document.write( "40 can be bought at $50.00 each. </SPAN>\n" );
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