document.write( "Question 279767: find the equation, in standard form, of the parabola\r
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Algebra.Com's Answer #203378 by Edwin McCravy(20060) $\"\"$ $\"About$

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$\"3y%5E2%2B6y-x%2B6=0\"$
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document.write( "Standard form is\r\n" );
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document.write( "Get the y-terms on the left and the others on the right:\r\n" );
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document.write( "Divide through by 3, the coefficient of :\r\n" );
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document.write( "Complete the square on the left:\r\n" );
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document.write( "1. Multiply the coefficient of y, which is 2 by , getting 1\r\n" );
document.write( "2. Square 1, getting 1\r\n" );
document.write( "3. Add 1 to both sides:\r\n" );
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document.write( "Factor the left side as a perfect square, combine terms on the right.\r\n" );
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document.write( "Factor out , the coefficient of x on the right,\r\n" );
document.write( "by dividing the  by  like this:  \r\n" );
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document.write( "So we have the standard form:\r\n" );
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document.write( "Edwin

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