document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=279776>Question 279776</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the center of a circle with the equation:x^2+y^2-6x + 10y +24 = 0\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #203371 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=203371\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x^2 + y^2 - 6x + 10y = -24\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "x^2 - 6x + 9 + y^2 + 10y + 25 = 10\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "(x - 3)^2 + (y + 5)^2 = 10\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "center is (3, -5) </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );