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Hi there. I have been working 15x+5y=10 for quite some time now. Please help with plotting it on a graph. I am getting (1,5) and (3,-10) and it's not the right answer. Thanks in advance. \r
\n" ); document.write( "\n" ); document.write( "15x + 5y = 10
\n" ); document.write( "5y = -15x + 10 (rearranged)
\n" ); document.write( "y = -3x + 2 (divided both sides by 5)
\n" ); document.write( "since the equation of a line is y=mx+b where m is the slope and b is the y-intercept (vertical intercept or point (0,b)) -->
\n" ); document.write( "slope = m = -3
\n" ); document.write( "y-intercept = b = 2
\n" ); document.write( "check (1,5) to see if it is on the line:
\n" ); document.write( "5 = -3(1) + 2
\n" ); document.write( "5 = -3 + 2
\n" ); document.write( "5 = -1
\n" ); document.write( "no that is not true, (1,5) is not on the line
\n" ); document.write( "check (3,-10) to see if that is on the line:
\n" ); document.write( "-10 = -3(3) + 2
\n" ); document.write( "-10 = -9 + 2
\n" ); document.write( "-10 = -7
\n" ); document.write( "no that is also not true, (3,-10) is also not on the line
\n" ); document.write( "what would be on the line?
\n" ); document.write( "x=-5 --> y=-3(-5) + 2 = 15 + 2 = 17
\n" ); document.write( "x=-1 --> y=-3(-1) + 2 = 3 + 2 = 5
\n" ); document.write( "x=0 --> y=-3(0) + 2 = 2 (your y-intercept)
\n" ); document.write( "x=1 --> y=-3(1) + 2 = -3 + 2 = -1
\n" ); document.write( "x=5 --> y=-3(5) + 2 = -15 + 2 = -13
\n" ); document.write( "graphing:
\n" ); document.write( "