document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=279678>Question 279678</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How would you figure the probability of choosing 2 cards from a deck and getting 2 kings or 2 black cards?\r<BR>\n" );
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document.write( "Well for starters with picking two black cards you  have a fifty fifty Shot. Thw reson for this is because there is and even amount of black cards and red cards/ You have 26 of each. When it comes to picking out two kings. You will have aboue a 3.8 percent chance of accomplishing this. To figue this all you need to do is take 2/52=.038 move the decimal to the right two spots and you have 3.8%. Hope this helps you!!! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #203302 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=203302\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> How would you figure the probability of choosing 2 cards from a deck and getting 2 kings or 2 black cards?<BR>\n" );
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document.write( "P(2kings or 2 black cards) = P(2 kings) + P(2 black cards) - P(2k and 2b)<BR>\n" );
document.write( "= 4C2/52C2 + 26C2/52C2 - 1/52C2<BR>\n" );
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document.write( "= [4C2 + 26/2 -1]/52C2<BR>\n" );
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document.write( "= [6 + 325 - 1]/52C2<BR>\n" );
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document.write( "= 330/1326<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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