document.write( "Question 33940: hi, need help with simplifying complex number
\n" ); document.write( "i^51, have no idea how to do it, if you can explain it please i will appreciate it
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Algebra.Com's Answer #20326 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
powers of \"i\" go thru a cycle; i, i^2=-1, i^3=-i, i^4=1
\n" ); document.write( "So, divide 51 by 4 to get 12 with a remainder of 3
\n" ); document.write( "Then i^51=[(i^4)^(12)](i^3)= [(1^12)][-i]= -i
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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