document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=30971>Question 30971</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A company wants to invest $180,000 in three accounts, one bearing 4.5%, another 6%, and another 8% interest.  Twice as much will be invested at 4.5% as at 8%, and the total interest earned the first year needs to be $10,400.  How much should be invested at each rate? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #20325 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=20325\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let amount invested at 8% be \"x\"; interest is 0.08x<BR>\n" );
document.write( "Then amount invested at 4% is\"2x\"; interest is 004(2x)=0.08x<BR>\n" );
document.write( "And amount invested at 6% is 0.06(180,000-3x); int. is 10,800-0.18x<BR>\n" );
document.write( "EQUATION:<BR>\n" );
document.write( "interest + interest + interest = $10,400<BR>\n" );
document.write( "0.08x+0.08x+10,800-0.18x=10,400<BR>\n" );
document.write( "Multiply thru by 100 to get:<BR>\n" );
document.write( "8x+8x+1080000-18x=1040000<BR>\n" );
document.write( "-2x-40000<BR>\n" );
document.write( "x=$20,000 (amount invested at 8%)<BR>\n" );
document.write( "2x=$40,000 (amount invested at 4%)<BR>\n" );
document.write( "180,000-3x=$120,000 (amount invested at 6%)<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );