document.write( "Question 279631: 1. The lens equation for a camera is 1/f = 1/di + 1/do , where f is the focal length of the lens, di is the distance between the lens and the film, and do is the distance between the lens and the object. For a certain camera, an object that is 18 cm from the lens is in focus when the lens is 9 cm from the film. What is the focal length of the lens?
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Algebra.Com's Answer #203246 by Theo(13342)\"\" \"About 
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1/f = 1/di + 1/do
\n" ); document.write( "f is the focal length of the lens
\n" ); document.write( "di is the distance between the lens and the film.
\n" ); document.write( "do is the distance between the lens and the object.\r
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\n" ); document.write( "\n" ); document.write( "object is 18 cm from the lens.
\n" ); document.write( "lens is 9 cm from the film.\r
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\n" ); document.write( "\n" ); document.write( "do = 18
\n" ); document.write( "di = 9\r
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\n" ); document.write( "\n" ); document.write( "1/f = 1/9 + 1/18\r
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\n" ); document.write( "\n" ); document.write( "1/9 is the same as 2/18 so this equation becomes:\r
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\n" ); document.write( "\n" ); document.write( "1/f = 2/18 + 1/18 = 3/18\r
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\n" ); document.write( "\n" ); document.write( "you have:\r
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\n" ); document.write( "\n" ); document.write( "1/f = 3/18\r
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\n" ); document.write( "\n" ); document.write( "since this is in the form of a ratio, you can cross multiply to get:\r
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\n" ); document.write( "\n" ); document.write( "3f = 18\r
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\n" ); document.write( "\n" ); document.write( "divide both sides of this equation by 3 to get:\r
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\n" ); document.write( "\n" ); document.write( "f = 6\r
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\n" ); document.write( "\n" ); document.write( "your answer is that the focal length of the lens is 6.\r
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\n" ); document.write( "\n" ); document.write( "you confirm by plugging that value into the equation to see that it is true.\r
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\n" ); document.write( "\n" ); document.write( "the equation is 1/f = 1/di + 1/do\r
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\n" ); document.write( "\n" ); document.write( "we had di = distance from lens to the film = 9 cm.\r
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\n" ); document.write( "\n" ); document.write( "we had do = distance from object to the lens = 18 cm.\r
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\n" ); document.write( "\n" ); document.write( "we have f = 6\r
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\n" ); document.write( "\n" ); document.write( "equation becomes:\r
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\n" ); document.write( "\n" ); document.write( "1/6 = 1/9 + 1/18\r
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\n" ); document.write( "\n" ); document.write( "convert all to denominator of 18 to get:\r
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\n" ); document.write( "\n" ); document.write( "3/18 = 2/18 + 1/18 which becomes:\r
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\n" ); document.write( "\n" ); document.write( "3/18 = 3/18 which is true confirming that the value of f = 6 is good.\r
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