document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=279627>Question 279627</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The amount of annual interest earned by $8,000 invested at a certain rate is $200 less than 12,000 would earn at a 1% lower rate. At what rate is the $8,000 invested? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #203241 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=203241\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The amount of annual interest earned by $8,000 invested at a certain rate is $200 less than 12,000 would earn at a 1% lower rate. At what rate is the $8,000 invested?\r<BR>\n" );
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document.write( "let the rate invested  be x\r<BR>\n" );
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document.write( "The interest earned = 8000*x/100\r<BR>\n" );
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document.write( "12000 is invested at (x-1)%\r<BR>\n" );
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document.write( "(x-1)/100*12000 -200 = 8000x/100\r<BR>\n" );
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document.write( "(x-1)*120-200 =80x\r<BR>\n" );
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document.write( "120x-120-200=80x\r<BR>\n" );
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document.write( "40x=320\r<BR>\n" );
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document.write( "x= 8%\r<BR>\n" );
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document.write( " </SPAN>\n" );
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