document.write( "Question 33800: [1,1] [0,3]
\n" ); document.write( " 2x+y=3
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Algebra.Com's Answer #20324 by fanism(39)\"\" \"About 
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the equation is:
\n" ); document.write( "x2-x1/y2-y1 = x-x1/y-y1
\n" ); document.write( "in your case,
\n" ); document.write( "x1, y1 = [1,1]
\n" ); document.write( "x2, y2 = [0,3]
\n" ); document.write( "therefore:
\n" ); document.write( "0-1/3-1 = x-1/y-1
\n" ); document.write( "-1/2 = x-1/y-1
\n" ); document.write( "-y+1=2x-2
\n" ); document.write( "0=2x+y-3
\n" ); document.write( "
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