document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=279618>Question 279618</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Investor Company loaned out a total of $36,000, part at 6% interest and part at 9% interest. They reported that the annual earnings from both investments were the same amount that would have been earned by the total loan if it had been invested at 8%. Find the amount loaned at each rate. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #203238 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16949)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=203238\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Investor Company loaned out a total of $36,000, part at 6% interest and part at 9% interest. They reported that the annual earnings from both investments were the same amount that would have been earned by the total loan if it had been \r<BR>\n" );
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document.write( "let x be invested at 6%\r<BR>\n" );
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document.write( "36000-x will be invested  at 9%\r<BR>\n" );
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document.write( "0.06x=0.09(36000-x) ( the interests on both are the same.)\r<BR>\n" );
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document.write( "0.06x= 3240. 00- 0.09x\r<BR>\n" );
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document.write( "0.15x= 3240\r<BR>\n" );
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document.write( "x=$21600  at 6 %\r<BR>\n" );
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document.write( "$36000-$21600= $24400 at 9%\r<BR>\n" );
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document.write( " </SPAN>\n" );
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