document.write( "Question 279459: A cross country skier walks 3000m up a mountain road, rests for 10 minutes and then skis down the road. he returns a half hour after he started. if he skis four times as fast as he walks, at what rate does he ski?\r
\n" ); document.write( "\n" ); document.write( "( having a hard time grasping these word problems and what dictates a constant factor and how to build the equation.
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Algebra.Com's Answer #203204 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
A cross country skier walks 3000m up a mountain road, rests for 10 minutes
\n" ); document.write( " and then skis down the road.
\n" ); document.write( " he returns a half hour after he started. if he skis four times as fast as
\n" ); document.write( " he walks, at what rate does he ski?
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\n" ); document.write( "Change half hour to 30 min
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\n" ); document.write( "Let w = his walking speed (in meters/minute)
\n" ); document.write( "then
\n" ); document.write( "4w = his skiing speed
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\n" ); document.write( "Write a time equation: time = dist/speed
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\n" ); document.write( "up time + 10 min + down time = 30 min
\n" ); document.write( "\"3000%2Fw\" + 10 + \"3000%2F%284w%29\" = 30
\n" ); document.write( "Multiply by 4W,results
\n" ); document.write( "4(3000) + 4w(10) + 3000 = 4w(30)
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\n" ); document.write( "12000 + 40w + 3000 = 120w
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\n" ); document.write( "12000 + 3000 = 120w - 40w
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\n" ); document.write( "15000 = 80w
\n" ); document.write( "w = \"15000%2F80\"
\n" ); document.write( "w = 187.5 m/min; his walking speed
\n" ); document.write( "and
\n" ); document.write( "4(187.5) = 750 m/min is his skiing speed
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\n" ); document.write( "That would be: \"%28750%2A60%29%2F1000\" = 45 km/hr
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\n" ); document.write( "Check solution by finding the times
\n" ); document.write( "3000/187.5 = 16 min
\n" ); document.write( "resting time:10 min
\n" ); document.write( "3000/750.0 = 4 min
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\n" ); document.write( "total time = 30 min; confirms our solution
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