document.write( "Question 279490: The sum of the digits of a two- digit number is 12. If 36 is added to the number, then the number obtained is the original with its digits interchanged. Find the original number. \n" ); document.write( "
Algebra.Com's Answer #203165 by solver91311(24713)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "Let represent the 10s digit. Let represent the 1s digit.\r
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\n" ); document.write( "\n" ); document.write( "The sum of the digits is 12 so: \r
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\n" ); document.write( "\n" ); document.write( "The value of the original number must be:\r
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\n" ); document.write( "\n" ); document.write( "Adding 36\r
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\n" ); document.write( "\n" ); document.write( "The value of the number with the digits reversed must be:\r
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\n" ); document.write( "\n" ); document.write( "So:\r
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\n" ); document.write( "\n" ); document.write( "Which is to say:\r
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\n" ); document.write( "\n" ); document.write( "Or\r
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\n" ); document.write( "\n" ); document.write( "Add that last equation to the first equation:\r
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\n" ); document.write( "\n" ); document.write( "That means must be 12 - 4 = 8 and that makes the original number be 48.\r
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\n" ); document.write( "\n" ); document.write( "Check 48 plus 36 is 84 which is 48 with the digits reversed.\r
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