document.write( "Question 279305: A plane flying the 3020-mile trip from City A to City B has a 60-mph tailwind. The flight's point of no return is the point at which the flight time required to return to City A is the same as the time required to continue to City B. If the speed of the plan in still air is 430 mph, how far from City A is the point of no return?
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Algebra.Com's Answer #203162 by ankor@dixie-net.com(22740)\"\" \"About 
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A plane flying the 3020-mile trip from City A to City B has a 60-mph tailwind.
\n" ); document.write( " The flight's point of no return is the point at which the flight time required
\n" ); document.write( "to return to City A is the same as the time required to continue to City B.
\n" ); document.write( " If the speed of the plan in still air is 430 mph, how far from City A is the
\n" ); document.write( " point of no return?
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\n" ); document.write( "Determine the speeds
\n" ); document.write( "430+60 = 490 mph toward city B (with the wind)
\n" ); document.write( "430-60 = 370 mph back to city A (against the wind)
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\n" ); document.write( "Let d = distance from City A to the point of no return
\n" ); document.write( "then
\n" ); document.write( "(3020-d) = distance from city B to this point
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\n" ); document.write( "At this point the travel time to each city will be the same
\n" ); document.write( "Write a time equation; Time = dist/speed
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\n" ); document.write( "Time to return against the wind = time to continue with the wind
\n" ); document.write( "\"d%2F370\" = \"%28%283020-d%29%29%2F490\"
\n" ); document.write( "Cross multiply
\n" ); document.write( "490d = 370(3020-d)
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\n" ); document.write( "490d = 1117400 - 370d
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\n" ); document.write( "490d + 370d = 1117400
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\n" ); document.write( "860d = 1117400
\n" ); document.write( "d = \"1117400%2F860\"
\n" ); document.write( "d = 1299.3 miles from A
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\n" ); document.write( "You can prove this: 3020 - 1299.3 = 1720.7 to city B
\n" ); document.write( "Time back to A: 1299.3/370 = 3.511 hrs
\n" ); document.write( "Time on to B: 1720.7/490 = 3.511 hrs also
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\n" ); document.write( "Did this make sense to you?
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