document.write( "Question 279231: Find the area of a regular hexagon with the given measurement.\r
\n" ); document.write( "\n" ); document.write( "4-inch side\r
\n" ); document.write( "\n" ); document.write( "A = sq. in.
\n" ); document.write( "

Algebra.Com's Answer #203081 by CharlesG2(834)\"\" \"About 
You can put this solution on YOUR website!
Find the area of a regular hexagon with the given measurement.
\n" ); document.write( "4-inch side
\n" ); document.write( "A = sq. in.\r
\n" ); document.write( "\n" ); document.write( "from http://www.mathopenref.com/polygonregulararea.html:
\n" ); document.write( "\"+area+=+%28S%5E2+%2A+N%29%2F%284+%2A+tan%28pi%2FN%29%29+\"
\n" ); document.write( "where
\n" ); document.write( "S is the length of any side
\n" ); document.write( "N is the number of sides
\n" ); document.write( "\"+pi+\" is PI, approximately 3.142
\n" ); document.write( "TAN is the tangent function calculated in radians\r
\n" ); document.write( "\n" ); document.write( "\"+area+=+%284%5E2+%2A+6%29%2F%284+%2A+tan%28pi%2F6%29%29+\"
\n" ); document.write( "\"+area+=+%2816+%2A+6%29%2F%284+%2A+sqrt%283%29%2F3%29+\"
\n" ); document.write( "\"+tan%28pi%2F6%29+=+sqrt%283%29%2F3+=+approximately+0.57735027+\"
\n" ); document.write( "\"+area+=+96%2F%284+%2A+sqrt%283%29%2F3%29+\"
\n" ); document.write( "\"+area+=+24%2F%28sqrt%283%29%2F3%29+\"
\n" ); document.write( "\"+area+=+24+%2A+3%2Fsqrt%283%29+\"
\n" ); document.write( "\"+area+=+72%2Fsqrt%283%29+\"
\n" ); document.write( "\"+area+=+%2872+%2A+sqrt%283%29%29%2F3+\"
\n" ); document.write( "\"+area+=+24sqrt%283%29+\"
\n" ); document.write( "\"+area+=+approximately+41.569+square+inches+\"\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( " \r
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" );