document.write( "Question 279246: I am in desperate need of help on this problem.\r
\n" ); document.write( "\n" ); document.write( "x^1/2-4x^1/4=-3
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Algebra.Com's Answer #203076 by Earlsdon(6294)\"\" \"About 
You can put this solution on YOUR website!
\"x%5E%281%2F2%29+-+4x%5E%281%2F4%29+=+-3\" Solve for x:
\n" ); document.write( "If you can make this equation look more like a standard quadratic equation, then you can ease your desperation.
\n" ); document.write( "Try a change of variable like this:
\n" ); document.write( "\"x%5E%281%2F4%29+=+y\", then \"x%5E%281%2F2%29+=+y%5E2\" Make these substitions to get:
\n" ); document.write( "\"y%5E2-4y+=+-3\" Add 3 to both sides to get:
\n" ); document.write( "\"y%5E2-4y%2B3+=+0\" Now you can see that you have a standard quadratic equation in y, so now we solve for y.
\n" ); document.write( "\"y%5E2-4y%2B3+=+0\" Factor.
\n" ); document.write( "\"%28y-1%29%28y-3%29=+0\" so that...
\n" ); document.write( "\"y+=+1\" or \"y+=+3\" Now substitute \"y+=+x%5E%281%2F4%29\"
\n" ); document.write( "\"x%5E%281%2F4%29+=+1\" or \"x%5E%281%2F4%29+=+3\" In both solutions, raise both sides to the 4th power.
\n" ); document.write( "\"%28x%5E%281%2F4%29%29%5E4+=+1%5E4\" or \"%28x%5E%281%2F4%29%29%5E4+=+3%5E4\" Evaluate:\"3%5E4+=+81\"
\n" ); document.write( "\"highlight%28x+=+1%29\" or \"highlight%28x+=+81%29\"
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