document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=279245>Question 279245</A>: <I><SPAN STYLE=\"word-break: break-all;\"> graph the line which passes through the point (6,-1) and is perpendicular to the line with equation 2x-6y=-14 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #203069 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=203069\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> graph the line which passes through the point (6,-1) and is perpendicular to the line with equation 2x-6y=-14<BR>\n" );
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document.write( "The given line has a slope = 1/3<BR>\n" );
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document.write( "Any perpendicular line must have a slope of -3.<BR>\n" );
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document.write( "Form: y = mx + b<BR>\n" );
document.write( "You know m = 1/3 and y = -1 when x = 6; solve for \"b\":<BR>\n" );
document.write( "-1 = (1/3)(6) + b<BR>\n" );
document.write( "-1 = 2 + b<BR>\n" );
document.write( "b = -3<BR>\n" );
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document.write( "Ans: y = -3x -3<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. <BR>\n" );
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