document.write( "Question 279073: The cable TV industry reports that 59% of homes in the US to cable TV. If you pick four US households at random, what is the probability that at least one of the households is not a cable TV subscriber? \n" ); document.write( "
Algebra.Com's Answer #203044 by stanbon(75887)\"\" \"About 
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The cable TV industry reports that 59% of homes in the US to cable TV. If you pick four US households at random, what is the probability that at least one of the households is not a cable TV subscriber?
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\n" ); document.write( "Binomial Problem:
\n" ); document.write( "n = 4 ; p = 0.59 ; q = 0.41 ; 1<= x <=4
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\n" ); document.write( "P(at least one) = 1 - P(none)
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\n" ); document.write( "P(at least DISABLED_event_one= 1 - 4C0(0.59)^0*(0.41)^4 = 1-0.41^4 = 0.9717...
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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