document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=279094>Question 279094</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Brittany can run a mile in 6 minutes and Christina can run a mile in 9 minutes. If both Brittany and Christina start running at the same time and Brittany starts 1/3 of a mile behind Christina, how long will it take Brittany to catch up with Christina? I know that Brittany runs at 1/6 miles per minute, Christina runs at 1/9 miles per minute, and distance is rate multiplied by time. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #202989 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=202989\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> brittany 60/6=10 mph<BR>\n" );
document.write( "christina 60/9=20/3=6 2/3 mph<BR>\n" );
document.write( "60x/6=60x/9+1/3<BR>\n" );
document.write( "rt=rt+d<BR>\n" );
document.write( "10x=20x/3+1/3<BR>\n" );
document.write( "30x=20x+1<BR>\n" );
document.write( "10x=1<BR>\n" );
document.write( "x=1/10=6 minutes\r<BR>\n" );
document.write( "\n" );
document.write( "check<BR>\n" );
document.write( "10*1/10=20/3*1/10+1/3<BR>\n" );
document.write( "1=2/3+1/3<BR>\n" );
document.write( "1=1<BR>\n" );
document.write( "ok </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );