document.write( "Question 279094: Brittany can run a mile in 6 minutes and Christina can run a mile in 9 minutes. If both Brittany and Christina start running at the same time and Brittany starts 1/3 of a mile behind Christina, how long will it take Brittany to catch up with Christina? I know that Brittany runs at 1/6 miles per minute, Christina runs at 1/9 miles per minute, and distance is rate multiplied by time. \n" ); document.write( "
Algebra.Com's Answer #202982 by stanbon(75887)\"\" \"About 
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Brittany can run a mile in 6 minutes and Christina can run a mile in 9 minutes. If both Brittany and Christina start running at the same time and Brittany starts 1/3 of a mile behind Christina, how long will it take Brittany to catch up with Christina?
\n" ); document.write( "I know that Brittany runs at 1/6 miles per minute, Christina runs at 1/9 miles per minute, and distance is rate multiplied by time.
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\n" ); document.write( "Brittany DATA:
\n" ); document.write( "distance = [x+(1/3)] miles ; rate = (1/6)mi/min ; time = [(3x+1)/3]/(1/6) =
\n" ); document.write( "2(3x+1) = 6x+2 min\r
\n" ); document.write( "\n" ); document.write( "--------------------------------
\n" ); document.write( "Christina DATA;
\n" ); document.write( "distance = x mile rate = 1/9 mi/m ; time = x/(1/9) = 9x min
\n" ); document.write( "-------------------------------------
\n" ); document.write( "Equation:
\n" ); document.write( "time = time
\n" ); document.write( "6x+2 = 9x
\n" ); document.write( "3x = 2
\n" ); document.write( "x = 2/3
\n" ); document.write( "Brittaney's time = 6 min = Christina's time
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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