document.write( "Question 279065: Anita has two sisters and three brothers. The mean of all their ages is 6 years. What will their mean age be 10 years from now? Twenty years from now? \n" ); document.write( "
Algebra.Com's Answer #202967 by Mr.Gardner(4)![]() ![]() ![]() You can put this solution on YOUR website! This is how I answered the question. If you let the siblings be represented by the letters a,b,c,d,e,f (there are six of them including Anita), then you can set up the following equation:\r \n" ); document.write( "\n" ); document.write( "(a+b+c+d+e+f)/6 = 6. \r \n" ); document.write( "\n" ); document.write( "This comes from the formula for a mean. \r \n" ); document.write( "\n" ); document.write( "In ten years, each sibling will have added 10 years to their age, so this is the equation for the mean of their ages ten years from now:\r \n" ); document.write( "\n" ); document.write( "[(a+10)+(b+10)+(c+10)+(d+10)+(e+10)+(f+10)]/6\r \n" ); document.write( "\n" ); document.write( "By adding all of the 10's in the numerator we get:\r \n" ); document.write( "\n" ); document.write( "(60+a+b+c+d+e+f)/6\r \n" ); document.write( "\n" ); document.write( "We can seperate this fraction into:\r \n" ); document.write( "\n" ); document.write( "60/6 + (a+b+c+d+e+f)/6\r \n" ); document.write( "\n" ); document.write( "60/6 = 10 and we know that (a+b+c+d+e+f)/6 = 6, so the answer is:\r \n" ); document.write( "\n" ); document.write( "10+6 = 16.\r \n" ); document.write( "\n" ); document.write( "So in ten years the mean age increased 10 years.\r \n" ); document.write( "\n" ); document.write( "Using the same arithmetic we get that the mean age in 20 years will have increased 20 years, so the answer to the second question is 26. \n" ); document.write( " |