document.write( "Question 278259: 2log x-log x^3 = 4
\n" ); document.write( "solve for x
\n" ); document.write( "how I started the problem
\n" ); document.write( "log (x^2/X^3)=4
\n" ); document.write( "then
\n" ); document.write( "(x^2/x^3)=10^4
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Algebra.Com's Answer #202939 by jsmallt9(3758)\"\" \"About 
You can put this solution on YOUR website!
\"x%5E2%2Fx%5E3=10%5E4\"
\n" ); document.write( "Great start! You've done all the hard work. The rest is just simplify:
\n" ); document.write( "\"1%2Fx=10000\"
\n" ); document.write( "... and solve:
\n" ); document.write( "Multiply both sides by x:
\n" ); document.write( "\"1+=+10000x\"
\n" ); document.write( "Divide both sides by 10000:
\n" ); document.write( "\"1%2F10000+=+x\"

\n" ); document.write( "With logarithmic equations you should always check your answers. You must make sure that none of the logarithms end up with a zero or negative argument. A quick visual check of the original equation tells you that 1/10000 will not make the argument of either logarithm zero or negative. So this answer checks.
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