document.write( "Question 278886: 1/3 of the coins are nickels, 4/9 are dimes. i have only dimes, nickels and silver dollars.total 5.10/ how many of each coin do i have?
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Algebra.Com's Answer #202908 by checkley77(12844)\"\" \"About 
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.05(1x/3)+.10(4x/9)+1(2x/9)=5.10
\n" ); document.write( ".05x/3+.4x/9+2x/9=5.10
\n" ); document.write( "(.05x*3+.4x+2x)/9=5.10
\n" ); document.write( "(.15x+2.4x)/9=5.10 cross multiply
\n" ); document.write( "2.55x=5.10*9
\n" ); document.write( "2.55x=45.90
\n" ); document.write( "x=45.90/2.55
\n" ); document.write( "x=18 ans. for the total number of coins.
\n" ); document.write( "Nickels=1/3*18=6 ans.
\n" ); document.write( "Dimes=4/9*18=8 ans.
\n" ); document.write( "Dollars=2/9*18=4 ans.
\n" ); document.write( "Proof:
\n" ); document.write( ".05*6+.10*8+1*4=5.10
\n" ); document.write( "5.10=5.10
\n" ); document.write( ".30+.80+4=5.10
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