document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=4462>Question 4462</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A flower bed is in the shape of a rectangle.  Its length is twice its width.  The bed is surrounded by a walkway 4 feet wide.  If the area of the walkway is exactly twice the area of the bed, find the dimensions of the bed. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #2029 by </B><A HREF=/tutors/aboutme.mpl?userid=rapaljer><B>rapaljer(4671)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rapaljer><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rapaljer><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=2029\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Begin by drawing a rectangle whose width is x, and whose length is 2x.  Add another rectangle outside this rectangle that extends 4 feet in each direction from the inner rectangle.  The width of the outer rectangle is x+8, and the length of the outer rectangle is 2x+8, since you have to add 4 feet TWICE in each direction.\r<BR>\n" );
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document.write( "The area of the inner rectangle is LW = x(2x) or <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2x%5E2 ALIGN=MIDDLE  ALT=\"2x%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" >.<BR>\n" );
document.write( "The area of the outer rectangle is LW = (x+8)(2x+8) or <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2x%5E2+%2B+24x+%2B+64 ALIGN=MIDDLE  ALT=\"2x%5E2+%2B+24x+%2B+64\"   DISABLED_style= \"max-width:90%; height:auto;\" >.<BR>\n" );
document.write( "Area of walkway = outer area - inner area <BR>\n" );
document.write( "= <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2x%5E2+%2B+24x+%2B+64+-+2x%5E2 ALIGN=MIDDLE  ALT=\"2x%5E2+%2B+24x+%2B+64+-+2x%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "= <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=24x+%2B+64 ALIGN=MIDDLE  ALT=\"24x+%2B+64\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "Equation:  Area of walkway equals twice inner area (area of the bed):<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=24x+%2B+64=+2%2A%282x%5E2%29 ALIGN=MIDDLE  ALT=\"24x+%2B+64=+2%2A%282x%5E2%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > .<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=24x+%2B+64+=+4x%5E2 ALIGN=MIDDLE  ALT=\"24x+%2B+64+=+4x%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "Quadratic equations, so set equal to zero by subtracting 24x and 64 from both sides.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=0+=+4x%5E2+-+24x+-+64+=+0 ALIGN=MIDDLE  ALT=\"0+=+4x%5E2+-+24x+-+64+=+0\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "Factor out the common factor of 4:<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=0=4%28x%5E2+-+6x+-+16%29+ ALIGN=MIDDLE  ALT=\"0=4%28x%5E2+-+6x+-+16%29+\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "Factor the trinomial:<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=0+=+4%28x-8%29%28x%2B2%29+ ALIGN=MIDDLE  ALT=\"0+=+4%28x-8%29%28x%2B2%29+\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "Solutions are x = 8 and x = -2, but x represents the side of a rectangle, so it cannot be negative. \r<BR>\n" );
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document.write( "Final answer: <BR>\n" );
document.write( "x = 8  width of bed. <BR>\n" );
document.write( "2x = 16 length of bed.\r<BR>\n" );
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document.write( "Check: <BR>\n" );
document.write( "Dimensions of the walkway<BR>\n" );
document.write( "x+8 = 16<BR>\n" );
document.write( "2x+8= 24<BR>\n" );
document.write( "Area of bed = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=8%2A16 ALIGN=MIDDLE  ALT=\"8%2A16\"   DISABLED_style= \"max-width:90%; height:auto;\" > = 128 sq. ft.<BR>\n" );
document.write( "Total area = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=16%2A24 ALIGN=MIDDLE  ALT=\"16%2A24\"   DISABLED_style= \"max-width:90%; height:auto;\" > = 384 sq. ft.<BR>\n" );
document.write( "Area of walk = 384 - 128 = 256 sq. ft.\r<BR>\n" );
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document.write( "Area of walk = 2(area of bed)<BR>\n" );
document.write( "256 = 2(128)\r<BR>\n" );
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document.write( "R^2 at SCC </SPAN>\n" );
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