document.write( "Question 278906: How do i solve x^2+6x+13=0 by using the quadratic formula?
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Algebra.Com's Answer #202899 by checkley77(12844) $\"\"$ $\"About$

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x^2+6x+13=0
\n" ); document.write( " $\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"$
\n" ); document.write( "x=(-6+-sqrt(6^2-4*1*13])/2*1
\n" ); document.write( "x=(-6+-sqrt[36-52])/2
\n" ); document.write( "x=(-6+-sqrt-16)/2
\n" ); document.write( "x=(-6+-4i)/2
\n" ); document.write( "x=-6/2+-4i/2
\n" ); document.write( "x=-3+-2i ans. \n" ); document.write( "

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