document.write( "Question 278824: Joe has a collection of nickels and dimes that is worth $5.65. If the number of dimes were doubled and the number of nickels were increased by 8, the value of the coins would be $10.45. How many dimes does he have? \n" ); document.write( "
Algebra.Com's Answer #202815 by Stitch(470)\"\" \"About 
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Set-Up
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\n" ); document.write( "Let A = Number of Nickels
\n" ); document.write( "Let b = Number of Dimes
\n" ); document.write( "Equation 1: \"A%2A0.05+%2B+B%2A0.1+=+5.65\"
\n" ); document.write( "Equation 2: \"%28A+%2B+8%29%2A0.05+%2B+2%2AB%2A0.1+=+10.45\"\r
\n" ); document.write( "\n" ); document.write( "Solution:
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\n" ); document.write( "You can divide every term in equation 1 by .05
\n" ); document.write( "Equation 1: \"A%2A0.05+%2B+B%2A0.1+=+5.65\"
\n" ); document.write( "\"A+%2B+2B+=+113\" Subtract 2B from both sides
\n" ); document.write( "\"A+=+113+-+2B\"\r
\n" ); document.write( "\n" ); document.write( "Now we can plug (113 - 2B) into equation 2 for A
\n" ); document.write( "Equation 2: \"%28A+%2B+8%29%2A0.05+%2B+2%2AB%2A0.1+=+10.45\"
\n" ); document.write( "\"%28%28113+-+2B%29+%2B+8%29%2A0.05+%2B+2%2AB%2A0.1+=+10.45\" Simplify
\n" ); document.write( "\"%28121+-+2B%29%2A0.05+%2B+B%2A0.2+=+10.45\" Simplify
\n" ); document.write( "\"6.05+-+0.1%2AB+%2B+0.2%2AB+=+10.45\" Simplify
\n" ); document.write( "\"6.05+%2B+0.1B+=+10.45\" Subtract 6.05 from both sides
\n" ); document.write( "\"0.1B+=+4.40\" Divide both sides by 0.1
\n" ); document.write( "\"highlight%28B+=+44%29\"\r
\n" ); document.write( "\n" ); document.write( "Now plug 44 into the modified equation 1 for B
\n" ); document.write( "\"A+=+113+-+2B\"
\n" ); document.write( "\"A+=+113+-+2%2A%2844%29\"
\n" ); document.write( "\"A+=+113+-+88\"
\n" ); document.write( "\"highlight%28A+=+25%29\"
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