document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=33863>Question 33863</A>: <I><SPAN STYLE=\"word-break: break-all;\"> what is the soultion to this simultaneous equation using substion or addtion method<BR>\n" );
document.write( "x+2y=15<BR>\n" );
document.write( "x-2y=-9 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #20280 by </B><A HREF=/tutors/aboutme.mpl?userid=sarah_adam><B>sarah_adam(201)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=sarah_adam><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=20280\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x+2y=15   --- eq 1<BR>\n" );
document.write( "x-2y=-9   --- eq 2<BR>\n" );
document.write( "-------<BR>\n" );
document.write( "2x = -6       (adding eq1 and eq2)<BR>\n" );
document.write( "x = -6/2 = -3\r<BR>\n" );
document.write( "\n" );
document.write( "substitute value of x in eq 1<BR>\n" );
document.write( "2y = 15 - x<BR>\n" );
document.write( "2y = 15 - (-3)<BR>\n" );
document.write( "2y = 15+3 = 18<BR>\n" );
document.write( "y = 18/2 = 9\r<BR>\n" );
document.write( "\n" );
document.write( "x = -3; y = 9<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );