document.write( "Question 278791: If a 2000 dollar investment grows to 5000 dollars in 14 years, with interest compounded annually, what is the intrest rate?\r
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Algebra.Com's Answer #202788 by Theo(13342)\"\" \"About 
You can put this solution on YOUR website!
formula is:\r
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\n" ); document.write( "\n" ); document.write( "f = p * (1+i)^n\r
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\n" ); document.write( "\n" ); document.write( "f = future value
\n" ); document.write( "p = present amount
\n" ); document.write( "i = annual interest rate compounded annually
\n" ); document.write( "n = number of time periods in years\r
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\n" ); document.write( "\n" ); document.write( "you have:\r
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\n" ); document.write( "\n" ); document.write( "f = 5000
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\n" ); document.write( "i = i
\n" ); document.write( "n = 14\r
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\n" ); document.write( "\n" ); document.write( "your formula becomes:\r
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\n" ); document.write( "\n" ); document.write( "5000 = 2000 * (1+i)^14\r
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\n" ); document.write( "\n" ); document.write( "divide both sides of this formula by 2000 to get:\r
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\n" ); document.write( "\n" ); document.write( "5000/2000 = (1+i)^14\r
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\n" ); document.write( "\n" ); document.write( "Take the log of both sides of this equation to get:\r
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\n" ); document.write( "\n" ); document.write( "log(5000/2000) = log(1+i)^14)\r
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\n" ); document.write( "\n" ); document.write( "since log (x^a) = a*log(x), your formula becomes:\r
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\n" ); document.write( "\n" ); document.write( "log(5000/2000) = 14 * log(1+i)\r
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\n" ); document.write( "\n" ); document.write( "divide both sides of this equation by 14 to get:\r
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\n" ); document.write( "\n" ); document.write( "log(1+i) = log(5000/2000)/14\r
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\n" ); document.write( "\n" ); document.write( "Use your calculator to find tghe log of (5000/2000) and you get:\r
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\n" ); document.write( "\n" ); document.write( "log(1+i) = .397940009/14\r
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\n" ); document.write( "\n" ); document.write( "Simplify to get:\r
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\n" ); document.write( "\n" ); document.write( "log(1+i) = .028424286\r
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\n" ); document.write( "\n" ); document.write( "Use your calculator to find the number whose log is .028424286 and you get:\r
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\n" ); document.write( "\n" ); document.write( "1+i = 1.067638647\r
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\n" ); document.write( "\n" ); document.write( "Subtract 1 from both sides of this equation to get:\r
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\n" ); document.write( "\n" ); document.write( "i = .067638647 which is equivalent to 6.7638647%\r
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\n" ); document.write( "\n" ); document.write( "Your annual interest rate is .067638647 which is equivalent to 6.7638647% per year when expressed as a percent.\r
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\n" ); document.write( "\n" ); document.write( "Plug this rate (not the percent) back into your original equation, which is:\r
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\n" ); document.write( "\n" ); document.write( "5000 = 2000 * (1+i)^14\r
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\n" ); document.write( "\n" ); document.write( "replace i with .067638647 to get:\r
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\n" ); document.write( "\n" ); document.write( "5000 = 2000 * (1.067638647)^14\r
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\n" ); document.write( "\n" ); document.write( "Simplify to get:\r
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\n" ); document.write( "\n" ); document.write( "5000 = 2000 * 2.5 = 5000 confirming that the interest rate of .067638647 is good.\r
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