document.write( "Question 278773: The radiator of a car holds 16 quarts of liquid of which 8 are antifreeze. The radiator has a leak and loses 2 quarts of liquid each week. Every week 2 quarts of water are added. After 3 weeks how much antifreeze is left in the radiator?
\n" ); document.write( "I know the amount of the mixture is diluted each time water is poured in, so less and less antifreeze is present after each week. I am not sure how to show the amount of antifreeze left. after each week.
\n" ); document.write( "There are 8/16 Antifreeze and 8/16 water, but after loosing 2 quarts of antifreeze there will be 9/16 water and 7/16 of antifreeze after the water has been added. This is where I am not sure how to proceed. \n" ); document.write( "

Algebra.Com's Answer #202777 by vleith(2983) $\"\"$ $\"About$

You can put this solution on YOUR website!
Here's a hint. Instead of focusing on the percentage of quarts, focus on the total percentage.\r
\n" ); document.write( "\n" ); document.write( "So as you noted, after adding the water at the end of the first week, there will again be 16 quarts in the radiator. But now, instead of 50% being anitfreeze, only 7/16 or 43.75% is antifreeze.\r
\n" ); document.write( "\n" ); document.write( "Now let another week go by and two more quarts leak out. Now there are 14 quarts left in the radiator -- with a density of 43.75% antifreeze.\r
\n" ); document.write( "\n" ); document.write( "So 14*0.4375 = 6.125 quarts of antifreeze are left.\r
\n" ); document.write( "\n" ); document.write( "Add two more quarts of water and do the same type logic above.
\n" ); document.write( "Etc
\n" ); document.write( "Hope that helps \n" ); document.write( "

\n" );