document.write( "Question 278767: Jack and Jim start at the same time to ride from place A to place B, 60 miles away. Jack travels 4 miles an hour slower than Jim. Jim reaches B and at once turns back meeting Jack 12 miles from B.The rate of Jack was:\r
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document.write( "(A) 4 mph (B) 8 mph (C) 12 mph (D) 16 mph (E) 20 mph \n" );
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Algebra.Com's Answer #202769 by Grinnell(63)![]() ![]() ![]() You can put this solution on YOUR website! Good Morning! \n" ); document.write( " Immediately, you have to recognize the fact that Jim travels 72 miles in the same time that Jack travels 48 \n" ); document.write( "miles. Don't get 'twisted' in the turn-around--they want to confuse 'ya. Sooo, \n" ); document.write( "let x be the speed (or mph) that Jim travels \n" ); document.write( "let x-4 be the speed Jack travels. \n" ); document.write( " \r \n" ); document.write( "\n" ); document.write( "x TIMES (time) =72 miles \n" ); document.write( "(x-4) TIMES (time) =48 miles \n" ); document.write( "Note, the time is the Konstant, or 'the same' Hey why don't we just divide both \n" ); document.write( "equations by the TIME or the Konstant? \n" ); document.write( "let t represent (time) \n" ); document.write( "x=72/t \n" ); document.write( "x-4=48/t \n" ); document.write( "Let's substitute, off to the races... \n" ); document.write( "72/t-4=48/t \n" ); document.write( "72-4t=48 (multiplied thru by t) \n" ); document.write( "-4t=-24 \n" ); document.write( "t=6--not finished yet! NOW we go back and plug in our 't'. \n" ); document.write( "x(6)=72 \n" ); document.write( "x is 12, go all the way back to the beginning ...this is Jim's speed \n" ); document.write( "12-4, or 8 is Jack's speed. \n" ); document.write( "Have a wonderful day! \n" ); document.write( " |