document.write( "Question 278495: a train leaves a station at 1pm travelling at 40mph. Another train leaves the same station at 2pm travelling at 60mph. What time will it be when the two trains first meet? \n" ); document.write( "
Algebra.Com's Answer #202684 by ankor@dixie-net.com(22740) You can put this solution on YOUR website! a train leaves a station at 1pm traveling at 40mph. \n" ); document.write( " Another train leaves the same station at 2pm traveling at 60mph. \n" ); document.write( " What time will it be when the two trains first meet? \n" ); document.write( ": \n" ); document.write( "Let t = travel time of the 60 mph train \n" ); document.write( "then \n" ); document.write( "(t+1) = travel time of the 50 mph train \n" ); document.write( ": \n" ); document.write( "When one train overtakes the other train, they will have traveled the same distance \n" ); document.write( ": \n" ); document.write( "Write a distance equation: dist = speed * time \n" ); document.write( "60t = 50(t+1) \n" ); document.write( "60t = 50t + 50 \n" ); document.write( "60t - 50t = 50 \n" ); document.write( "10t = 50 \n" ); document.write( "t = 5 hrs \n" ); document.write( ": \n" ); document.write( "2 PM + 5 hrs = 7 PM \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Confirm solution by finding the distances \n" ); document.write( "60(5) = 300 \n" ); document.write( "50(6) = 300 mi \n" ); document.write( " |