document.write( "Question 278532: A PIN code has 3 letters. How many different PIN codes are possible if 3 of the same letter are not allowed (like AAA), but two of the same are allowed (AAB,ABA and BAA)? \n" ); document.write( "
Algebra.Com's Answer #202670 by nyc_function(2741)\"\" \"About 
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Let's use AAB.\r
\n" ); document.write( "\n" ); document.write( "3P3 = 3!/(3 - 3)!\r
\n" ); document.write( "\n" ); document.write( "3P3 = 6/0!\r
\n" ); document.write( "\n" ); document.write( "3P3 = 6/1\r
\n" ); document.write( "\n" ); document.write( "3P3 = 6 different PIN codes are possible.\r
\n" ); document.write( "\n" ); document.write( "Or you can do it the long way.\r
\n" ); document.write( "\n" ); document.write( "AAB becomes AA, AB, BA = 2 letters + 2 letters + 2 letters = 6 letters or PINS.
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