document.write( "Question 278532: A PIN code has 3 letters. How many different PIN codes are possible if 3 of the same letter are not allowed (like AAA), but two of the same are allowed (AAB,ABA and BAA)? \n" ); document.write( "
Algebra.Com's Answer #202670 by nyc_function(2741)![]() ![]() You can put this solution on YOUR website! Let's use AAB.\r \n" ); document.write( "\n" ); document.write( "3P3 = 3!/(3 - 3)!\r \n" ); document.write( "\n" ); document.write( "3P3 = 6/0!\r \n" ); document.write( "\n" ); document.write( "3P3 = 6/1\r \n" ); document.write( "\n" ); document.write( "3P3 = 6 different PIN codes are possible.\r \n" ); document.write( "\n" ); document.write( "Or you can do it the long way.\r \n" ); document.write( "\n" ); document.write( "AAB becomes AA, AB, BA = 2 letters + 2 letters + 2 letters = 6 letters or PINS. \n" ); document.write( " |