document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=278478>Question 278478</A>: <I><SPAN STYLE=\"word-break: break-all;\"> To prepare two liters of a 10% solution from a pure drug, you would need ____? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #202648 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=202648\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> To prepare two liters of a 10% solution from a pure drug, you would need ____?<BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "Let x be the amount of water you add.<BR>\n" );
document.write( "pure drug + water = 10% mix<BR>\n" );
document.write( "1.00(2-x) + 0(x) = 0.10*2<BR>\n" );
document.write( "Multiply thru by 100 to get:<BR>\n" );
document.write( "100*2 - 100x + 0 = 10*2 <BR>\n" );
document.write( "-100x = -90*2<BR>\n" );
document.write( "x = 1.8 liters  (amt. of water needed for the mixture<BR>\n" );
document.write( "----<BR>\n" );
document.write( "2-x = 0.2 liters (amt. of pure drug needed for the mixture<BR>\n" );
document.write( "==================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );