document.write( "Question 278360: Write the slope-intercept form of the equation
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Algebra.Com's Answer #202603 by jim_thompson5910(35256)\"\" \"About 
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Solved by pluggable solver: Converting Linear Equations in Standard form to Slope-Intercept Form (and vice versa)
Convert from standard form (Ax+By = C) to slope-intercept form (y = mx+b)


\"3x-2y=-16\" Start with the given equation


\"3x-2y-3x=-16-3x\" Subtract 3x from both sides


\"-2y=-3x-16\" Simplify


\"%28-2y%29%2F%28-2%29=%28-3x-16%29%2F%28-2%29\" Divide both sides by -2 to isolate y


\"y+=+%28-3x%29%2F%28-2%29%2B%28-16%29%2F%28-2%29\" Break up the fraction on the right hand side


\"y+=+%283%2F2%29x%2B8\" Reduce and simplify


The original equation \"3x-2y=-16\" (standard form) is equivalent to \"y+=+%283%2F2%29x%2B8\" (slope-intercept form)


The equation \"y+=+%283%2F2%29x%2B8\" is in the form \"y=mx%2Bb\" where \"m=3%2F2\" is the slope and \"b=8\" is the y intercept.


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