document.write( "Question 278419: A chemist has one solution that is 80% acid and another solution that is 30% acid. How much of the first (80%) solution is needed to make a 400 L solution that is 62% acid? \n" ); document.write( "
Algebra.Com's Answer #202599 by richwmiller(17219)![]() ![]() You can put this solution on YOUR website! .8*x+.3*(400-x)=.62*400 \n" ); document.write( "x=256 400-x=144 \n" ); document.write( "256 L of 80% \n" ); document.write( "144 L of 30%\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |