document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=278377>Question 278377</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Give the polar coordinates: (-2, 2). </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #202585 by </B><A HREF=/tutors/aboutme.mpl?userid=nyc_function><B>nyc_function(2741)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nyc_function><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nyc_function><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=202585\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> We need to convert to the form (r, theta). \r<BR>\n" );
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document.write( "Graph the given point on the xy-plane. \r<BR>\n" );
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document.write( "We drop a perpendicular line from (-2,2) to the x-axis forming a right triangle.<BR>\n" );
document.write( "The value of x = -2 and the value of y = 2.\r<BR>\n" );
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document.write( "We now need to find the radius.  \r<BR>\n" );
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document.write( "r = sqrt{(-2)^2 + (2)^2}\r<BR>\n" );
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document.write( "r = sqrt{8})\r<BR>\n" );
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document.write( "r = 2(sqrt{2})\r<BR>\n" );
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document.write( "We now need to find the value of theta.\r<BR>\n" );
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document.write( "We can use any trig function to find theta.\r<BR>\n" );
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document.write( "The tangent function = y/x.  We know the values of x and y.\r<BR>\n" );
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document.write( "So, tan(theta) = 2/-2\r<BR>\n" );
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document.write( "Since theta is an angle, we need to use the tangent inverse key on the calculator.\r<BR>\n" );
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document.write( "We say that theta is -45 degrees in this example.\r<BR>\n" );
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document.write( "So, our final answer is (2(sqrt{2}), -45).\r<BR>\n" );
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document.write( "nycfunction@yahoo.com<BR>\n" );
document.write( "Guidio\r<BR>\n" );
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document.write( " </SPAN>\n" );
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