document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=278389>Question 278389</A>: <I><SPAN STYLE=\"word-break: break-all;\"> f(x)=1/3^x raised to the x power for x values -3, -2, -1, 0, 1, 2, 3 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #202556 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=202556\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> f(x)=(1/3)^x raised to the x power for x values -3, -2, -1, 0, 1, 2, 3<BR>\n" );
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document.write( "Note: The negative on the exponent is an instruction; it says \"invert <BR>\n" );
document.write( "the base\".<BR>\n" );
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document.write( "f(-3) = (1/3)^(-3) = 3^3 = 27<BR>\n" );
document.write( "f(-2) = (1/3)^(-2) = 3^2 = 9<BR>\n" );
document.write( "f(-1) = (1/3)^-1 = 3<BR>\n" );
document.write( "f(0) = (1/3)^x = 1<BR>\n" );
document.write( "f(1) = (1/3)^1 = 1/3<BR>\n" );
document.write( "f(2) = (1/3)^2 = 1/9<BR>\n" );
document.write( "f(3) = (1/3)^3 = 1/27<BR>\n" );
document.write( "======================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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