document.write( "Question 278369: The perimeter of a triangle is 45 inches. The fist side is twice the length of the second, and the third side is 5 inches longer than the second. Find the length of each side. \n" ); document.write( "

Algebra.Com's Answer #202544 by JBarnum(2146) $\"\"$ $\"About$

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a+b+c=45
\n" ); document.write( "a=2b
\n" ); document.write( "c=5+b
\n" ); document.write( "substitute and solve for b, then a and c.
\n" ); document.write( " $\"2b%2Bb%2B5%2Bb=45\"$ add
\n" ); document.write( " $\"4b%2B5=45\"$ subtract
\n" ); document.write( " $\"4b=40\"$ divide
\n" ); document.write( " $\"highlight%28b=10%29\"$ second
\n" ); document.write( "a=2b
\n" ); document.write( " $\"a=2%2810%29\"$
\n" ); document.write( " $\"highlight%28a=20%29\"$ first
\n" ); document.write( "c=5+b
\n" ); document.write( " $\"c=5%2B%2810%29\"$
\n" ); document.write( " $\"highlight%28c=15%29\"$ third \n" ); document.write( "

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