document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=278350>Question 278350</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Give sufficient examples to convince someone that the sum of three consecutive integers will always be a multiple of 3.Note:0 is a multiple of 3 x 0. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #202532 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=202532\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> if we let x = the number, then we get\r<BR>\n" );
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document.write( "x + x + 1 + x + 2 = 3x + 3\r<BR>\n" );
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document.write( "we can always divide 3x + 3 by 3 to get x + 1.\r<BR>\n" );
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document.write( "not only is the number divisible by 3, but it will always be the middle number in the sequence.\r<BR>\n" );
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document.write( "some examples:\r<BR>\n" );
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document.write( "1 + 2 + 3 = 6 / 3 = 2\r<BR>\n" );
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document.write( "17 + 18 + 19 = 54 / 3 = 18\r<BR>\n" );
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document.write( "153 + 154 + 155 = 462 / 3 = 154\r<BR>\n" );
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document.write( " </SPAN>\n" );
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