document.write( "Question 278342: Sum of present ages of a man and his son is 60 years. Five years ago the mans age was 4 times his sons age. Then find their present ages. \n" ); document.write( "
Algebra.Com's Answer #202528 by mananth(16946)\"\" \"About 
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Sum of present ages of a man and his son is 60 years. Five years ago the mans age was 4 times his sons age. Then find their present ages.\r
\n" ); document.write( "\n" ); document.write( "Let the son's age be x\r
\n" ); document.write( "\n" ); document.write( "Father's age will be 60-x\r
\n" ); document.write( "\n" ); document.write( "5 years ago\r
\n" ); document.write( "\n" ); document.write( "(60-x) -5 = (x-5) *4\r
\n" ); document.write( "\n" ); document.write( "300-5x -5= 4x-20\r
\n" ); document.write( "\n" ); document.write( "300+20-5=4x+5x\r
\n" ); document.write( "\n" ); document.write( "315= 9x
\n" ); document.write( "x=25 years\r
\n" ); document.write( "\n" ); document.write( "FAther's age = 60-25 = 35.\r
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