document.write( "Question 278342: Sum of present ages of a man and his son is 60 years. Five years ago the mans age was 4 times his sons age. Then find their present ages. \n" ); document.write( "
Algebra.Com's Answer #202528 by mananth(16946)![]() ![]() You can put this solution on YOUR website! Sum of present ages of a man and his son is 60 years. Five years ago the mans age was 4 times his sons age. Then find their present ages.\r \n" ); document.write( "\n" ); document.write( "Let the son's age be x\r \n" ); document.write( "\n" ); document.write( "Father's age will be 60-x\r \n" ); document.write( "\n" ); document.write( "5 years ago\r \n" ); document.write( "\n" ); document.write( "(60-x) -5 = (x-5) *4\r \n" ); document.write( "\n" ); document.write( "300-5x -5= 4x-20\r \n" ); document.write( "\n" ); document.write( "300+20-5=4x+5x\r \n" ); document.write( "\n" ); document.write( "315= 9x \n" ); document.write( "x=25 years\r \n" ); document.write( "\n" ); document.write( "FAther's age = 60-25 = 35.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |