document.write( "Question 278296: A rectangle is 8 cm longer than it is wide. Find the dimensions of the rectangle if its area is 240 sq-cm.\r
\n" ); document.write( "\n" ); document.write( "length = cm
\n" ); document.write( "width = cm
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Algebra.Com's Answer #202523 by mananth(16946)\"\" \"About 
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Let the width be x\r
\n" ); document.write( "\n" ); document.write( "length = x+8\r
\n" ); document.write( "\n" ); document.write( "x(x+8) =240
\n" ); document.write( "x^2+8x=240\r
\n" ); document.write( "\n" ); document.write( "x^2+8x-240=0\r
\n" ); document.write( "\n" ); document.write( "x^2 +20x-12x-240=0\r
\n" ); document.write( "\n" ); document.write( "x(x+20)-12(x+20)=0\r
\n" ); document.write( "\n" ); document.write( "(x+20)(x-12)=0\r
\n" ); document.write( "\n" ); document.write( "x=-20 0r 12\r
\n" ); document.write( "\n" ); document.write( "12, and 20
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