document.write( "Question 278284: 2x/3 + 3y/4 = 11/12
\n" ); document.write( "x/3 + 7y/18 = 1/2
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Algebra.Com's Answer #202517 by stanbon(75887)\"\" \"About 
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2x/3 + 3y/4 = 11/12
\n" ); document.write( "x/3 + 7y/18 = 1/2
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\n" ); document.write( "Multiply thru 1st equation by 12
\n" ); document.write( "Multiply thru 2nd equation by 18
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\n" ); document.write( "8x + 9y = 11
\n" ); document.write( "6x + 7y = 9
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\n" ); document.write( "Multiply thru 1st equation by 6
\n" ); document.write( "Multiply thru 2nd equation by 8
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\n" ); document.write( "48x + 54y = 66
\n" ); document.write( "48x + 56y = 72
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\n" ); document.write( "Subtract 1st from 2nd1st and solve for \"y\":
\n" ); document.write( "2y = 6
\n" ); document.write( "y = 3
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\n" ); document.write( "Substitute into 6x+7y = 9 to solve for \"x\":
\n" ); document.write( "6x + 7*3 = 9
\n" ); document.write( "6x = -12
\n" ); document.write( "x = -2
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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