document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=278287>Question 278287</A>: <I><SPAN STYLE=\"word-break: break-all;\"> you have $3.70 in dimes and quarters, you have 5 more quarters than dimes, how many how each coin do you have using substitution method. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #202512 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=202512\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> you have $3.70 in dimes and quarters, you have 5 more quarters than dimes, how many how each coin do you have using substitution method.\r<BR>\n" );
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document.write( "Let the dimes be x\r<BR>\n" );
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document.write( "The quarters will be x+5\r<BR>\n" );
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document.write( "The sum of their values = 370 cents\r<BR>\n" );
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document.write( "10x+25(x+5)=370\r<BR>\n" );
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document.write( "10x+25x+125=370\r<BR>\n" );
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document.write( "35x=370-125\r<BR>\n" );
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document.write( "x=245/35\r<BR>\n" );
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document.write( "x=7 which is the number of dimes\r<BR>\n" );
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document.write( "x+7=  7+5= 12 which is the number of quarters\r<BR>\n" );
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document.write( " </SPAN>\n" );
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