document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=278076>Question 278076</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Train A is traveling at 100 miles per hour, and train b is traveling at 104 miles per hour/ Train A passes the station at 4:25 a.m and train B passes the station at 4:55 a.m. What time will train B catch up to train A? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #202502 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=202502\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Train A is traveling at 100 miles per hour, and train b is traveling at 104 miles per hour/ Train A passes the station at 4:25 a.m and train B passes the station at 4:55 a.m. What time will train B catch up to train A?<BR>\n" );
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document.write( "Train A goes 50 miles from 525 to 455 (100 mph x 1/2 hour)<BR>\n" );
document.write( "Train B gains on train A at 4 mph (104 - 100)<BR>\n" );
document.write( "50 miles/4 mph = 12.5 hours<BR>\n" );
document.write( "0455 + 12.5 = 5:25 PM the same day<BR>\n" );
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