document.write( "Question 278214: four years ago, marion was 2/3 as old as les was.now she is 3/4 as old as he is. how old is each now?\r
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document.write( "I know that i have to always compare the ages in the same time, so i have
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document.write( "2/3m=L
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document.write( "3/4m plus 4=L plus 4
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document.write( "I am fairly certain the second equation is wrong. \n" );
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Algebra.Com's Answer #202484 by scott8148(6628)![]() ![]() You can put this solution on YOUR website! M = \"Marion NOW\" ___ L = \"Les NOW\"\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "\"four years ago, marion was 2/3 as old as les was\" ___ M - 4 = 2/3 (L - 4)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "\"now she is 3/4 as old as he is\" ___ M = (3/4) L\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "substituting ___ (3/4)L - 4 = 2/3 (L - 4)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "9 L - 48 = 8L - 32 ___ L = 16\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "substituting ___ M = (3/4)(16) = 12 \n" ); document.write( " |